C Programming Question 7 : C Programming Reference Question Bank

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19/07/07 - 560 Views - Ratings :   3.5 of 5 / 2 Votes

Level - Beginner

Question -

What will be  the output of the following code and why?


#include <stdio.h>

void main()
{
  int x,y;
  x = 5;
  y = ++x *   ++x;
  printf("Value of x = %d and Value of y = %d\n",x,y);
}

Answer -

Value of  of x = 7 and Value of y = 49

Explanation -

Not a very tough question. Important thing to note that in any expression pre increment operator has a higher prority than arithemetic operator as a result value of x is increment is first two times then value of y is evaluated. So y = 7*7 = 49.

This question will result in same output for most of the compilers, but some rare compiler may produce an entire diffrenent parse tree resulting in an undefined result.

Reader Comments -

Author

Comments

Flower

Dumb me! I never knew that pre and post increments will update the variable. I thought y = (++x) * (++x) = (6) * (7) = 42.
And also, I thought the incremented value of X will never get updated in X. So, from my poor understanding I thought the answer would be: x=5; y=42.

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